length of an arc curve

label Calculus
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

May 18th, 2015

dx/dy = y² - 1/(4y²) 

1 + (y² - 1/(4y²))² = (16y^8 + 8y⁴ + 1)/(16y⁴) = (4y⁴ + 1)²/(4y²)² 

√(1 + (dx/dy)²) = √((4y⁴ + 1)²/(4y²)²) = (4y⁴ + 1)/(4y²) = y² + 1/(4y²) 

₃ 
∫(y² + 1/(4y²)) dy = [y³/3 - 1/(4y)]₁³ = 9 - 1/12 - 1/3 + 1/4 = 53/6 ≈ 8.83 
¹

May 18th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
May 18th, 2015
...
May 18th, 2015
Aug 17th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer