Word Problem with Prealgebra

label Algebra
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schedule 1 Day
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A rectangle has a 120 feet perimeter, the length is 5 times the width, what is the length and width of the rectangle

May 18th, 2015

Hello! Hope this helps :)

P = Perimeter

L = Length

W = Width

Now set up these two equations.  One general equation for perimeter and another equation relating length to width.

P = 2L + 2W

120 = 2L + 2W

L = 5W

Now plug L = 5W into the perimeter equation:

120 = 2*(5W) + 2W

Solve for W:

120 = 10W + 2W

120 = 12W

W = 10 feet

Now plug W into the length/width equation:

L = 5*10

L = 50 feet

Please let me know if you have any questions :)

May 18th, 2015

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