What is the mass of 2.54 ml of H2 at 195 0
C and 850 mmHg?
Can you show me the setup please
We need to use the deal gas law here: PV=nRT
n = # grams / MM (MM = molar mass in g/mol) PV = (mass in g / MM) x RT P = (mass in g / MM) x RT / V But, d = mass in g / V thus, P = dRT / MM
d = P x MM / RT=1.12atm*2 g/mol / (0.082*468.15K)=0.0584 g/L
m=d*V=0.0584 g/L * 0.00254L=1.48*10^-4 g
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