What is the volume of the atom of an element that crystallizes as a body-centered cube if the volume of the unit cell is 1.97 x 10-22 cm3 ?

Using the Pythagorean Theorem, we find:

d^{2} + d^{2} = (4r)^{2}

2d^{2} = 16r^{2}

r^{2} = d^{2} ÷ 8

r = d ÷ 2(√2)

r = 1.3748 x 10¯^{8} cm///////////////////////

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