tim kicks a ball off the ground. after t seconds, its height h ( in feet ), is given by the formula h=-16^2+64t. what is the maximum height reached by the ball

Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h = -16t^2 + 64t. What is the maximum height reached by the ball? ------------------ You have a quadratic with a = -16 and b = 64 The max occurs when t = -b/2a = -64/(2*-16) = 2 second

--------------------- The height at t = 2 sec is as follows: h(2) = -16(2)^2 + 64(2) = 64 ft///////////////////////////////////////////////

May 19th, 2015

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