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What is the volume of the atom of an element that crystallizes as a body-centered cube if the volume of the unit cell is 1.97 x 10-22 cm3 ?

I need step by step please

May 19th, 2015

Atoms are the tiny, complex building blocks of all matter. In a chemistry or physics class you might be asked to calculate the volume of an atom. This calculation is often done as a preparatory step in a more complex calculation to determine the volume of the atom's nucleus. Although the study of atoms can be difficult, the calculation of an atom's volume is not.

The atom is simply explained to be in the shape of cube.

"A unit cell" simply means that the atom has several cells but each one of them is 1.9 to the power of negative 22 cm cubed.

To calculate the volume, which is cubed shape, find the dimensions by using the provided volume cm3.

Calculate the cubic radius of an atom by multiplying the atomic radius by itself three times. For example, if the atomic radius is 5, you would multiply 5 by itself three times, which equals a cubic radius of 125.

Hope that helps

May 19th, 2015
First you have to realize that cell and the atom are both spheres, and that the cell is at the center of the atom.

The formula to calculate the volume of a sphere is:

V = 4/3 (pi) r3

May 19th, 2015

how do i calculate the volume of the atom though?

May 19th, 2015

Let me calculate that and get back to you shortly...

May 19th, 2015

can you show me the way you calculate it please

May 19th, 2015

I will try my best to provide you with what I have

May 19th, 2015
V = 4/3 (pi) r3

Step 1

1.97 x 10-22  = 4/3 x 22/7 x r3

Step 2

r3 = 1.97 x 10-22 x 3/4 x 7/22

Where: 10-22 means ten to power negative 22   and  I used 22/7 as the pi

to find the  r (radius) you will find the cube root of the answer you get in step 2

Please let me know if the question has additional information from what you provided

May 19th, 2015

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May 19th, 2015
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May 19th, 2015
Sep 26th, 2017
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