It takes 59 seconds for .50L of nitrogen gas to effuse through an apparatus. How many seconds for the same volume of 2 liters of hydrogen gas to effuse through the same apparatus?

explain in detail please

0.50 L = 59s

2 L = ? ... Cross multiply

= 2/0.5 x 59

= 4 x 59

= 236 seconds

what is the cross multiplication equation?

s is the time taken for 2 liters

so the equation is

s = 2/.5 x 59

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