It takes 59 seconds for .50L of nitrogen gas to effuse through an
apparatus. How many seconds for the same volume of 2 liters of
hydrogen gas to effuse through the same apparatus?
explain in detail please
0.50 L = 59s
2 L = ? ... Cross multiply
= 2/0.5 x 59
= 4 x 59
= 236 seconds
what is the cross multiplication equation?
s is the time taken for 2 liters
so the equation is
s = 2/.5 x 59
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