What is the temperature if the osmotic pressure of a solution is 2.07
atm, and the solution is made by adding 128 grams of a protein of
molar mass 2,805 g/mol to enough water to make 1500.0 ml of
STEP BY STEP EXPLANATION PLEASE!!!!!
Here you're going to use pi=MRT
pi = osmotic pressure = 2.07atm
M = molar concentration of dissolved protein = mol/liter
M = 0.456mol/1.5L = 0.0304mol/L......see below how to find V and n
V = 1.5Liters
n = solve for, given the protein information
n = (1mol/2.805kg)*.128kg = .0456mol
R = 0.08206 (L*atm)/(K*mol)
pi = MRT....solve for T
T = pi/(MR)
T = (2.07)/(0.0304*.08206)
Let me know if you have any questions :)
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