1) ...conservation of mass.
2) a. The eqn is balanced.
b. 15 moles of MnS are needed to produce 15 moles of MnCl2.
c. 36.5 g HCl x (1 mol HCl) / (36.4609 g HCl) x (1 mol H2S) / (2 mol HCl) x (34.0808 g H2S) / (1 mol H2S) = 17.08299 g
17.1 g H2S (with significant figures)
d. 50.0 g MnS x (1 mol MnS) / (87.003 g MnS) x (1 mol MnCl2) / (1 mol MnS) x (125.844 g MnCl2) / (1 mol MnCl2) = 72.32164 g 72.3 g H2S (with significant figures)
72.3 g H2S (with significant figures)
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