1&2.

Chemistry
Tutor: None Selected Time limit: 1 Day

May 19th, 2015

1) ...conservation of mass.

2) a. The eqn is balanced. 

     b. 15 moles of MnS are needed to produce 15 moles of MnCl2.

     c. 36.5 g HCl  x    (1 mol HCl) / (36.4609 g HCl)    x    (1 mol H2S) / (2 mol HCl)   x   (34.0808 g H2S) / (1 mol H2S) =  17.08299 g 

17.1 g H2S (with significant figures)

  

 d. 50.0 g MnS  x    (1 mol MnS) / (87.003 g MnS)    x    (1 mol MnCl2) / (1 mol MnS)   x   (125.844 g MnCl2) / (1 mol MnCl2) =  72.32164 g 

72.3 g H2S (with significant figures)

 

May 19th, 2015

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