#17 Precalculus questions

label Mathematics
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May 19th, 2015

Assume..
f(x) = sin² x/tan x...but..1/tan x = cot x
so..
f(x) = sin² x . cot x = sin² x . cosx/sinx = sin x . cosx = sinx.cosx

now.. multiply and divide by '2'

f(x) = 1/2 [ 2. sinx.cosx]

but.. 2 . sinx . cosx = Sin2x
so..f(x) = [Sin 2x]/2

Answer : sinx . cosx
or
[Sin 2x]/2 ....................................................5 star give me

May 19th, 2015

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May 19th, 2015
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