#17 Precalculus questions


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May 19th, 2015

Tanx=(sinx)/(cosx)  ... sin^2(x)/tanx=sin^2(x)*cosx/sinx  the sines cancel and your left with sinx*cosx ... sin2x=2cosxsinx.... 1/2*2sinxcosx=1/2sin2x

May 19th, 2015

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May 19th, 2015
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May 19th, 2015
Nov 22nd, 2017
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