What is the pH of a solution of .0300 M KHSO4?
Hey can you tell me equilibrium constants values for the questions, or any supplemetary values that might have been give. Thnks
Ka for HSO4 = 1.1X10^-2
You just need answer or complete explanation
if x = [H+], Then
Ka = x*x/(0.03-x)
0.011*(0.03-x) = x^2
x = 0.013
pH = -log[0.013]
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