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Cu+AgNo3-->Ag+Cu(NO2)2

How many grams of Ag are produced when 36.92 grams of Cu diplaces silver from silver nitrate in the above reaction?

May 20th, 2015

Can you counter check your equation. I understand

Cu + 2 AGNo3 -->Cu(No3)2 + 2 AG,  not Cu+AgNo3-->Ag+Cu(NO2)2

Then will shall discuss over the chat link.

May 20th, 2015

Sorry you are correct should read. _Cu+_AgNO3-->_AG+_Cu(NO3)2

May 20th, 2015

So let me work on it, just 10 minutes.

May 20th, 2015

Thank you so much.

May 20th, 2015

Balance the equation: Cu + 2 AGNo3 -->Cu(No3)2 + 2 AG.

Mass of copper = 36.92 grams.

No of moles of copper = its mass/ its molar mass.

Molar mass of copper = 63.5 grams.

No of moles = 36.92/63.5 = 0.5814 moles.

According to the balanced equation, 1 mole of  Cu produce 2 moles of Ag, so 0.5814 moles of Cu will produce 0.5814 x 2 moles of Ag, which is 1.1628 moles.

The molar mass of Ag is 107.87 grams.

So 1.1628 mole of Ag equals (107.87 x 1.1628) grams, which is approximately 125.43 grams.

Hope this  helps!  You can ask any question if you are not satisfied.

May 20th, 2015

Thank you so much for your help. I just could not figure it out. Thank you for clearing it up for me.

May 20th, 2015

Welcome! Thank you for your patience too.

May 20th, 2015

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May 20th, 2015
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May 20th, 2015
Dec 8th, 2016
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