Balance chemical equation first, and then calculate the answer.
How many grams of Al2O3 will be formed from 17.4 grams of Al?
Balanced chemical reaction is
2Al + 3O2 ---> 1Al2O3
Molecular mass of Al = 26.98 g/mol
So moles of Al = 17.4/26.98 = 0.645 moles
Now according to balanced chemical reactions
Molesof Al2O3 formed = 0.645/2 = 0.3225
So , mass of Al2O3 formed = 0.3225*molecular mass of Al2O3
=32.88 grams of Al2O3 is formed.
Thank you so much. I really appreciate your help.
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