How do I solve a problem about ratios and porportions?

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So my question says for every $70 dollars Susan saves Jane saves $21. Then it asks if Susan saves a total of $90 how much would Jane have? If Jane saves a total of $252 how much would Susan save? 

May 20th, 2015

For $70 saving of susan     jane saving is $21

hence 70 :90 :: 21:x

solving 70x = 90*21

x = 90*21/70 =27

hence for $90 saving of Susan , Jane will be saving $27  (Answer)

(2)

if Jane saved $252 then let y is saving of Susan

70 : y::21:252

solving we get,   21y = 252*70

or,   y = 252*70/21 = $ 840.

Answer : Susan Saving $840

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May 20th, 2015

thank you for your quick response 

can u explain more about how you got $27 for the first problem? I am confused on where the 90 came from during the problem 

May 20th, 2015

For $70 saving of susan  jane saving is $21

Now we need to find saving of Jane for Susan's Saving of $90 therefore

Susan saving (1) : Susan Saving (2)  :: Jane saving (1) : Jane Saving (2)

Susan saving (1) = $70  ; Susan Saving (2) =$90

Jane saving (1) = $21   ;   Jane saving (2) =  ???? (x) 

I hope you understood 70 :90 :: 21:x

To solve such problems we know that product of Extreme terms = product of middle terms

therefore we get , 70x = 90*21

70x =1890

dividing both side by 70 we get

70x/70 = 1890/70

or, x =27

Please don't forget to best my answer with some good comments

May 20th, 2015

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