1.f (x) = -3x^2+8x

y-intercept: x=0, then f(x)=-3*0+8*0=0, so (0,0)

axis of symmetry: x = -b/2a = -8/2*(-3) = 4/3

The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

x-coordinates of the vertex: x=4/3

x 0 1 4/3 2

y 0 5 16/3 4

1.png

2. f(x)=2x^2+7x+1

y-intercept: x=0, then f(x)=2*0+7*0+1=1, so (0, 1)

axis of symmetry: x = -b/2a =-7/2*2=-7/4

x-coordinates of the vertex: x=-7/4

x -2 -7/4 -1 0 1

y -5 -41/8 -4 1 10

2.png

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