DETERMINE THE NUMBER OF GRAMS AND VOLUME

Chemistry
Tutor: None Selected Time limit: 1 Day

May 20th, 2015

First we will start by determining the number of moles of NH3 produced.  For this we will also need the molar mass of N2 and NH3

Molar mass N2 = 2*14.0067 = 28.0134 g/mol N2

Molar mass NH3 = 14.0067 + 3*1.00794 =  17.03052 g /mol NH3

Now we start with the grams of N2 and work towards moles of NH3

37.5 g N2 * 1 mol N2 / 28.0134 g N2 * 2 mol NH3 / 1 mol N2 = 2.677 mol NH3

Now we can use the molar mass of NH3 to find the mass produced.

2.677 mol NH3 * 17.03052 g / mol NH3 = 45.596 g NH3 produced


Finally you can calculated the volume assuming STP (P = 1 atm and T = 273 K).  If you recall that 1 mole of gas at STP occupies 22.4 L.  You could also do this using the ideal gas law with the above temperature and pressure as well as the number of moles from above.

2.677 mol NH3 * 22.4 L / mol = 59.965 L of NH3.


If you were given other details about the temperature and pressure, then you would have to use the ideal gas law (PV = nRT)

Any additional questions about this problem please ask.

May 20th, 2015

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