Help find the sum of the first six terms of the geometric series?

2-6+18-54+...

a1 = 2,

r = -6/2 or -54/18 = -3

The formula finding the sum of GP when |r| < 1

is S = a(1−r^{n})/(1−r)

S = 2(1- (-3)^6)/(1-(-2)

= -364

Hope this helps. You can ask any question if you are not comfortable.

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