Help find the sum of the first six terms of the geometric series?
a1 = 2,
r = -6/2 or -54/18 = -3
The formula finding the sum of GP when |r| < 1
is S = a(1−rn)/(1−r)
S = 2(1- (-3)^6)/(1-(-2)
Hope this helps. You can ask any question if you are not comfortable.
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