word problem for mathematics

Mathematics
Tutor: None Selected Time limit: 1 Day

May 20th, 2015

2h+11= length

h= width

2h+13= diagnonal

(2h+13)^2= h^2+ (2h+11)^2

(2h+13)(2h+13)= h^2+ (2h+11)(2h+11)

4h^2+26h+26h+169= h^2+ 4h^2+22h+22h+121

4h^2+52h+169= h^2+4h^2+44h+121

4h^2-h^2-4h^2+52h-44h= 121-169

-h^2+8h+48=0

h^2-8h-48=0

h^2-12h+4h-48=0

h(h-12)+4(h-12)=0

(h+4) +(h-12)=0

h=-4

h=12

width= 12 inches



May 20th, 2015

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