word problem for mathematics

Mathematics
Tutor: None Selected Time limit: 1 Day

May 20th, 2015

area=LW

Area of swimming pool=18 x 22

=396 ft^2

area of warkway= 384 ft^2

Area difference

=(396 - 384)

let the length be x

(2x+22)(2x+18)-396=384

using quardratic formular 


 answer is 4fts

May 20th, 2015

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