the curve y=5x^2 meets x=1 at (1,1)
now the volume of cylinder is pi*r^2*h
volume of the semi-sphere is, (1/2)*[(4/3)*pi*r^3]
the volume of the result is pi-(2/3)*pi
volume of parabola is (pi/2)*h*r^2
now y=5x^2 and x=1 then the radius is 1 and the heght is y=5*(1)^2
please do the corrections
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