Suppose the base and height of a triangle sum to 12, amd teh area of the triangle is 16 sqaure cm

let base =b and height =h (b+h)=12 area of triangle = (1/2) * b*h (1/2) bh = 16 bh =16*2=32 h= 32/b Now (b+h)=12 (b+32/b ) = 12

multiply equation by b b^2+32=12b b^2-12b+32=0 b^2-8b-4b+32=0 b(b-8)-4(b-8)=0 (b-8)(b-4)=0 b=4 OR 8 if b=4 h=8 if b=8 h= 4

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