A random sample of Internet users was selected from the records of a large Internet provider and asked whether they would use the Internet or the Library to obtain information about health issues. Of these, 892 said they would use the Internet.

1.) The margin of error, MOE, that results from a 90% confidence interval of the proportion p^ that would use the internet rather than the library is...

Since no mean or standard deviation is provided or needed, I'm assuming the interval is simply 10% going in both directions, so 892/10 = 89.2. Now subtract and add that number to get the interval, which is 802.8 to 981.2. Hope this helps

I typed the prompt incorrectly, my fault, but its multiple choice... so here it goes again\

A random sample of 1400 Internet users was selected from the records of a large Internet provider and asked whether they would use the Internet or the Library to obtain information about health issues. Of these, 892 said they would use the Internet.