Suppose the base and height of a triangle sum to 12, and the area of the triangle is 16 square cm. What are the dimensions (base and height) of the triangle?
1. b + h = 12
substitute 1 in 2:
solve for b:
thus we have 2 solutions for b:
b1 = 8 , b2 = 4
accordingly we have 2 solutions for h
h1=4, h2 = 8
So we have 2 solutions: one with a base of 8 and height of 4 the other one is a base of 4 and height of 8.
Both solutions obey the requirements.
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