4^{x – 1} = 64^{x + 3}Step 1: 4^{x – 1} = 64^{x + 3}Step 2: 4^{x – 1} = (4^{3})^{x + 3}Step 3: 4^{x – 1} = 4^{3x + 9}

Which is the next step?

A: 4 = 3x + 9

B: x - 1 = -(3x + 9)

C: x - 1 = x + 3

D: x - 1 = 3x + 9

D: x - 1 = 3x + 9.......................

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