trigonometric derivatives

User Generated

xnlgevnan

Mathematics

Description

f(x)=[xsin2x+tan^4(x^7)]^5

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Explanation & Answer

f'(x)=5[xsin(2x)+tan^4(x^7)]^4 times the derivative of the expression within the bracket.
d/dx[xsin(2x)] =sin(2x)+2xcos(2x) --- (1)
d/dx[tan^4(x^7)]=4tan^3(x^7).sec^2(x^7...
=28x^6tan^3(x^7)sec^2(x^7) --- (2)
f'(x)=5[xsin(2x)+tan^4(x^7)]^4 [ (1)+(2)]


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