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The Lucas numbers L(n) part 2

Mathematics
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May 24th, 2015

L(k)= L(k-1)+ L(k-2)

   =α^(k-1)+β^(k-1) + (α +β)

   = α^(k-2) (α+1)+β^(k-2) (β+2)

   =α^(k-2) (α̂²)+β^(k-2) (β̂²)

   =α^k+β^k

Best of luck


May 24th, 2015

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