A ball is thrown vertically upward with a speed of 17.0 m/s.

a)The height to which ball rises s = t*(v + u)/2

an time will be t=(0-17)/-9.8= 1.735 seconds

the height reached is s=1.735*(17)/2= 14.75 m

b) t= 1.735 s

c)the height from ground is 14.75 m, the initial v=0 and acceleration is 9.8(gravity)

t=5.86/9.8

t=0.6 s

d)v=sqrt(2gs)

v=sqrt(2*9.8*14.75)

v=5.86 m/s

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