A ball is thrown vertically upward with a speed of 17.0 m/s.
a)The height to which ball rises s = t*(v + u)/2
an time will be t=(0-17)/-9.8= 1.735 seconds
the height reached is s=1.735*(17)/2= 14.75 m
b) t= 1.735 s
c)the height from ground is 14.75 m, the initial v=0 and acceleration is 9.8(gravity)
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