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What is the molarity of sodium hypochlorite (household bleach) made from 125grams of NaClO (74.44Grams/Moles), in 2.0 Liters of solution?

May 25th, 2015

We need the definition of molarity M= n/ V,

where:

n= number of moles of the solute

V= volume of the solution in Liters (L)

Now we need to calculate the number of moles of NaClO using the molar mass of NaOCl (74.44 g/ moles)

125g * (1 mole / 74.44g) = 1.68 moles of NaOCl

Now we are able to calculate the molarity M, since we have the number of moles of solute and the volumen of the solution in L (2.00L)

M= 1.68 moles of NaOCl / 2.00 L = 0.84 moles/L

May 25th, 2015

how does that work out I am confused

May 25th, 2015

I Use the definition of Molarity (M);

M=n/V

then I calculate the number of moles of NaOCl, using the molar mass of the compound.

With the number of moles  of NaOCl and the volume of the solution (2.00L) is easy to calculate the molarity of the solution. dividing the number of moles by the volume of the solution

May 25th, 2015

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May 25th, 2015
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May 25th, 2015
Dec 3rd, 2016
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