a1=300,d=50

Well, the first six terms are:

a1=300

a2=300+50=350

a3=350+50=400

a4=400+50=450

This repeats until

a6=550

a1=-8,d=5

Different problem, you need to ask a different question, amigo :)

What are the steps to a1=-8,d=5

Well, exactly the same as I did above: a1 is the beginning, and each successive step (a2, a3, a4) adds the 5 value. And then you begin again with the new a value.

a1=-8

a2 = -8 + 5 = -3

a3=-3+5=2

etc.

Can you answers these problems?

find A6 when a1=13,d=4

find a150 when a1=60,d=5

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