Find a6 when a1=13,d=4

Find a150 when a1=60,d=5

an=a1+(n-1)d

So

a6=a1+(6-1)d

---> a6=13+5*4=33

--->a6=33

and

a150=a1+(150-1)d

---> a150=60+(150-1)5

--->a150=805

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What is the answer to this problem

Find the sum of the first 25 terms of the arithmetic sequence: 7,19,31,43

Use the above formula, put

n=25

d=19-7=12

a1=7

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