Science
Physics Elastic Limit

Question Description

Two springs of negligible weight and of spring constants 100N/M respectively are connected end to end and suspended from a fixed point. Determine the total extension when a mass of 7.5 kg is hung from the lower end.

Show all your workings. Answer must be correct

Final Answer

Attached.

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Calculations on Hooke’s Law;
𝐹 = 𝑘𝑒, where F is force acting on the spring, k is the spring constant, e is the extension.
𝐹 = 𝑚𝑔 = 75 × 10 = 75𝑁
Therefore,
75 = 100 × 𝑒
Therefore, e will be given by
75

𝑒 = 100 = 0.75𝑚
When spri...

Teodorof (5628)
Rice University

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