Electric Field and Potential Difference

Content Type

User Generated

User

ZeUrael

Subject

Science

Description

Format: APA, Sources: 4 For this essay I will prepare the personal engagement part and the cover so you don't have to do it. All I ask is you to do the parts; Background information, development, method and conclusion. This internal assessment main aim is to do research so I chose this topic. I don't want to be rude but I have say it first that I can not afford any "plus tips" or something. I am saying this because I have faced with this situation before. Thank you for everything I will be open for any questions please do not hesitate to contact me.

Unformatted Attachment Preview

How the voltage across two oppositely charged metal plates affects the frequency of metal-covered a ping pong ball oscillating between them Two oppositely-charged parallel plates will produce an electric field between them. The electric field strength, E, between the two plates can be calculated using: E=V/d Where V is the potential difference across the two plates (in Volts) and d is the distance between the two plates (in meters). If a ping-pong ball is given a metal covering (e.g. aluminium foil) and is suspended between two parallel plates with a high potential difference across them, the ball will bounce back and forth between the plates; touching each plate in turn and collecting charge from the plate. This causes it to repel from the plate and accelerate to the other plate. The greater the potential difference across the plates, the greater the charge collected and thus the faster the frequency of oscillation. It is expected that as the potential difference increases, the frequency of oscillation of the ping pong ball will increase. STUDENT’S PERSONAL ENGAGEMENT: TIME, CLOCKS, ELECTROSTATICS, HIGH VOLTAGE SUPPLIES How the voltage across two oppositely charged metal plates affects the frequency of metal-covered a ping pong ball oscillating between them Two oppositely-charged parallel plates will produce an electric field between them. The electric field strength, E, between the two plates can be calculated using: E=V/d Where V is the potential difference across the two plates (in Volts) and d is the distance between the two plates (in meters). If a ping-pong ball is given a metal covering (e.g. aluminium foil) and is suspended between two parallel plates with a high potential difference across them, the ball will bounce back and forth between the plates; touching each plate in turn and collecting charge from the plate. This causes it to repel from the plate and accelerate to the other plate. The greater the potential difference across the plates, the greater the charge collected and thus the faster the frequency of oscillation. It is expected that as the potential difference increases, the frequency of oscillation of the ping pong ball will increase. STUDENT’S PERSONAL ENGAGEMENT: TIME, CLOCKS, ELECTROSTATICS, HIGH VOLTAGE SUPPLIES
Purchase answer to see full attachment

Tags: physics Electric field Potential difference

User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Explanation & Answer

Attached.

Running Head: ELECTRIC FIELD

1

Electric Field
Research Paper
Name
Institution Affiliation

ELECTRIC FIELD

2
Electric Field

The Electric Field is an electric property that assigns every point in a space with a
presented charge that is present in any form. The Electric Field Strength constitutes the
magnitude and direction of the electric field signified represented by the value E. It is also
known as electric field intensity or an electric field (Coletta, 2014, p.4). Through pointing at the
electric field at a specific point, the electric charge can be determined without knowing the
source that produced an electric field. In this case, a charge represents the electric field source
which goes forth to the space that surrounds it; as opposed to recognizing the electric force as
two electric charges directly interacting at a distance from each other. The extended force on the
second charge within the space is a direct interaction between the second charge and the electric
field. The electric field strength E is represented by the term Coulomb which is the exerted force
per unit electric charge, E = F/q. The second charge is doubled; the resultant forces also become
twice as great. The electric field E gets measured by the quotient gives the same measure at any
point. The source charge gives the strength of the electric field and a small test charge gives a
modification to the electric field. The electric field defined as a force per charge unit charge is
exert...