Description
Hi,
Need Help with Chapter 9 on Air Pollution Control A Design Approach, 4th Edition, by C. David Cooper and F.C. Alley, 2010. Text book Chapter 9. Can be found on Scribd Link Provided.
https://www.scribd.com/document/261409293/Air-Poll...
Only needed:
1-First Requirement
2-Second Requirement
3-Fifth Requirement
4-Sixth Requirement
5-Seventh Requirement
Explanation & Answer
Attached.
SOLUTION TO FIRST (1ST) REQUIREMENT
Question 1:
The mass emission rate of particles from the dryer is calculated by
52.0kg / hr 4.17kg / hr 47.83kg / hr
Question 2:
The percentages of the raw feed is calculated by
46.0
0.92 92%
50.0
Question 3:
The mass emission rate of SO2 is calculated by
0.9 * 6000 /1000 * 52 * 0.003
0.8424kg / hr
Question 4:
The concentration of particles emitted from the dryer is calculated by
Inlet air : wt % : N2 0.78*28 / 0.78*28 0.21*32 0.01*40 0.754
O2 = 0.232
Ar = 0.014
Feed rate : N2 = 0.754*18*52 g / std m3
0.754*18*52= 705.744 g / std m3
O2 = 217.15200 g / std m3
Ar = 13.104 g / std m3 kg/hr
Total = 18*52 = 936 g / std m3
Question 5:
The concentration of SO2 in the exhaust is calculated by
0.3*50000 = 15000 g / std m3
Convert to ppm
15000 g / std m3
1 g / std m3
57.3 ppm
2620 ppm
Question 6:
The require efficiency is calculated by
Fuel oil specific gravity = 0.9
=> fuel oil rate = 6000 * 0.90 = 5.4 kg/1000kg = 0.54%
Question 7:
The percentage of volume of moisture is calculated by
2.0% 0.9 46 100% 0.828 100% 82.8%
Question 8:
The exhaust gas flow rate is calculated by
0.30kg / kg 11.7% 18kg / kg 78%
= 14.091 kg / kg
Question 9:
The volume percentage of CO2 is calculated by
4.17
100% 8.02%
52
Similarly, the volume percentage of O2 is calculated by
18
100% 36%
50
SOLUTION TO SECOND (2ND) REQUIREMENT
Question 1:
The particle size distribution is log-normal because the d avg is calculated to be
d avg
02
1
2
Question 2:
The two (2) identical cyclones can be designed as follow:
dpc = [ 9 ...