101A Solve problems in elctromagnetic devices and related circuits

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Explanation & Answer

Attached.

PART B
3. Motor efficiency is
πœ‚=

π‘œπ‘’π‘‘π‘π‘’π‘‘
16000
=
π‘₯100% = 88.5%
π‘œπ‘’π‘‘π‘π‘’π‘‘ + π‘™π‘œπ‘ π‘ π‘’π‘  16000 + 1500 + 580

4. The short shunt connection of the DC compound generator is as follows:

240

Shunt field current, πΌπ‘ β„Ž = 125 = 1.92𝐴
Current through armature and series winding
πΌπ‘Ž = 45 + 1.92 = 46.92𝐴
Voltage drop on the series field wi...


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