# algebra based physics

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Question description

I have algebra based physics homework, I want you to solve the problems and show steps of how you get it.. That's it.

wolfram777
School: UCLA

Here's the solution. One of the answer is missing because there is no force value given. I can't do anything about it.If you can give me the values, i'll add the answer.

Chapter 9
a) Impulse is given by, Impuse = mΔv,
where m=mass (in kg), Δv=change in velocity (m/s)
0.0014
Impulse=
∗(8.1−0)=1.134∗10−5 kg m/s
1000
So,
b) Impulse is also given by, Impulse=FΔt,
where F=Force exerted (Newtons), Δt=time for which force is exerted (seconds).
0.37
1.134∗10−5=F∗
1000
So,
F=

1.134∗10−5∗1000
=0.03 N
0.37

Impulse is given by, Impuse = mΔv,
where m=mass (in kg), Δv=change in velocity (m/s)
So,
Impulse=1.4∗10−6∗(4.5−0)=6.3∗10−6 kg m/s
Impulse is also given by, Impulse=FΔt,
where F=Force exerted (Newtons), Δt=time for which force is exerted (seconds).
10
6.3∗10−5=F∗
1000
So,
F=6.3∗10−5∗100=6.3∗10−3 N

According to law of conservation of momentum, m1 u1 +m2 u 2=m1 v 1+m2 v 2 ,
where 1 & 2 denote the two objects, m=mass (kg), u=initial velocity (m/s), v=final velocity (m/s)
Putting in the values,
0.1∗1.2+1∗0=0.1∗(−0.85)+1∗v 2
0.12=−0.085+v 2
v 2=0.12+0.085=0.205 m/s [Speed of larger cart]
According to law of conservation of momentum, m1 u1 +m2 u 2=m1 v 1+m2 v 2 ,
where 1 & 2 denote the two objects, m=mass (kg), u=initial velocity (m/s), v=final velocity (m/s)
Putting in the values,
1.5∗0+0.1∗0=1.5∗v 1 +0.1∗45
0=1...

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Review

Anonymous
Awesome! Exactly what I wanted.

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