# Need help with Carbonic acid solution

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### Question Description

How many milliliters of 60% carbonic acid must be mixed with how many milliliters of 15% carbonic acid to make 650 milliliters of a 38% carbonic acid solution?

srikanthps123
School: New York University

Hello,have a nice day.I have attached complete document to solve the problem clearly if you have any query let me know
Hi, HelloHave a nice dayhere I have attached two files. One is for problem
solving, other is how to use the formula If you find any quiry in the solution, please let me know

Derivation of formula for calculation of Molarity (M) form percentage (%):

Mole is ratio of mass to molar mass of any substance, Mole =

mass of substance in grams
gram molecular weight

Molarity is ratio of number of moles to liter solution, Molarity (M) =

Numer of moles
volume of solution in liters

Substituting mole in molarity and volume usually taken in milliliters so converting liter into milliliters, we
will get

Molarity (M) =

mass of substance in grams (w)
1000
×
gram molecular weight (M wt) volume of solution in milliliters (V)

We can rewrite it as,
Molarity (M) =

mass of substance in grams (w)
10
× 100 ×
volume of solution in milliliters (V)
gram molecular weight (M wt)

% Method for grams of solute present in solution is defined as below. Substitute the below formula in
above equation gives the ...

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Anonymous
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