Precalc Worksheet and word key!

Anonymous
timer Asked: Oct 21st, 2018
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Question Description

This is very simple im going to provide the word key for this worksheet with all the answers and work provided your job is just to type them out on the blank fillable pdf version if there are words in the word key describing something just change it up so it not word for word but for the work shown thats fine All info will be below!

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Name Date: Precalculus A Sample Work – Unit 4: Polynomial and Rational Functions Remember to show all work to support your answers! 1. Identify the degree and describe the end behavior of the function:  = 4  −  +  − 1 2. Use the intermediate value theorem to show that the polynomial function has a real zero between the numbers given:  =  − 4 −  + 3; 0.5  1 3. Given the function  = 2 − 4  + 4 − 8 a. Use the rational root theorem to list all possible rational roots b. Use Descartes Rule of Signs to determine the number of positive and negative zeros 4. Use the remainder theorem and synthetic division to find the remainder when  =  − 5  − 11 + 8 is divided by  + 2 = 2 +   − 5 + 2 5. Use synthetic division to find the zeroes of :  6. For the following function, (a) state the domain, (b) identify all intercepts, (c) find any vertical or horizontal asymptotes, and (d) identify any removable discontinuities.      =    7. For the following function, (a) state the domain, (b) identify all intercepts, and (c) find any vertical or slant asymptotes.    = 8.        Divide and simplify the expressions:   ÷       ...
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Tutor Answer

Asirieng
School: Boston College

Attached.

Pre-Calculus-A sample work – Unit 4: Polynomial and rational functions
Remember to show all work to support your answers!
1. Identify the degree and describe the end behavior of the function
𝑓(𝑥) = 4𝑥 7 − 𝑥 5 + 𝑥 3 − 1

Degree: 7
End behavior:
𝑓(𝑥) → +∞ 𝑎𝑠 𝑥 → +∞
𝑓(𝑥) → +∞ 𝑎𝑠 𝑥 → +∞
2. Use the intermediate value theorem to show that the polynomial function has a real zero
between the numbers given.
𝑥 4 − 4𝑥 3 − 𝑥 + 3; 0.5 𝑎𝑛𝑑 1
𝑓(0.5) = 0.54 − 4(0.53 ) − 0.5 + 3
= 0.0625 ...

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