During a blood-donor program conducted during finals week for college students, a blood-pressure reading is taken first, revealing that out of 200 donors, 29 have hypertension. All answers to three places after the decimal. (I did most of these questions already, there are just a few I cannot solve. I starred the ones I have not solved and put the answers next to the question that I already answered. I only really need 2 out of 9. A 95% confidence interval for the true proportion of college students with hypertension during finals week is (____,____). (0.096, 0.1938)We can be 80% confident that the true proportion of college students with hypertension during finals week is (_____) with a margin of error of (_____). (0.145, 0.03187)Unless our sample (of 200 donors) is among the most unusual 10% of samples, the true proportion of college students with hypertension during finals week is between (_____) and (_____). (0.104, 0.186)The probability, at 60% confidence, that a given college donor will have hypertension during finals week is (_____) with a margin of error of (_____). (0.145, 0.210)* Assuming our sample of donors is among the most typical half of such samples, the true proportion of college students with hypertension during finals week is between (______) and (______). (not sure) *We are 99% confident that the true proportion of college students with hypertension during finals week is (_____) with a margin of error of (_____). (0.145, 0.064)Assuming our sample of donors is among the most typical 99.9% of such samples, the true proportion of college students with hypertension during finals week is (_____) and (_____). (0.063, 0.227)* Covering the worst-case scenario, how many donors must we examine in order to be 95% confident that we have the margin of error as small as 0.01? (_____). (not sure) *Using a prior estimate of 15% of college-age students having hypertension, how many donors must we examine in order to be 99% confident that we have the margin of error as small as 0.01? (_____). (8,487)