LEARN MORE...

Access Millions of academic & study documents

Building a Shower Equidistant to Campsites Geometry Problems

Content type
User Generated
Subject
Mathematics
Type
Worksheet
Showing Page:
1/3
Henry Prosser
Unit 5 Project
5/27/2020
Task 1:
Please reference above graph.

Sign up to view the full document!

lock_open Sign Up
Showing Page:
2/3
To build a shower equidistant to the campsites, the shower would have to be placed in the incenter of
the triangle. To do this, first you must find the perpendicular bisectors of lines BP, BH, and PH. Line BP is
(3,6), line PH is (8,6) and line BH is (7,2). The point where they meet is in the incenter. This is (6, 4.6) and
is where the shower should be placed.
Task 2:
A. The orthocenter of ∆ ABC is (5,1). To find the orthocenter I had to find the equation of the line
containing the altitude of AC. X= 2 because it is a horizontal line. The line with the altitude of BC
has a y value of -3. (2 − 5)/(4 − 5)
The orthocenter of ∆ ABO is the same as point a (2,2). The orthocenter of ∆ ACO is point B (5,5)
and the orthocenter of ∆ BCO is point c (2,2). What I found is that the orthocenter becomes the
vertex of the other triangles.
B. No it will not be the same for acute and right triangles. To find an orthocenter you need three
altitudes. An orthocenter of a right triangle is the vertex of the right angle. This means that the
point O will be the same as point B. ( I used triangle ABC with A (2,2), B (2,1) and C (3,1).) You
cannot find the orthocenter since the points are the same.
For an acute triangle, it also does not work. The orthocenter of an acute triangle is inside the
triangle. I used coordinates A (2,3) B (0,4) and C (1,2) with an orthocenter of (1.3, 2.6). The
orthocenter became a coordinate outside of the triangle when I used O as one of the triangle’s
vertexes instead of another existing point.

Sign up to view the full document!

lock_open Sign Up
Showing Page:
3/3

Sign up to view the full document!

lock_open Sign Up
Unformatted Attachment Preview
Henry Prosser Unit 5 Project 5/27/2020 Task 1: Please reference above graph. To build a shower equidistant to the campsites, the shower would have to be placed in the incenter of the triangle. To do this, first you must find the perpendicular bisectors of lines BP, BH, and PH. Line BP is (3,6), line PH is (8,6) and line BH is (7,2). The point where they meet is in the incenter. This is (6, 4.6) and is where the shower should be placed. Task 2: A. The orthocenter of ∆ ABC is (5,1). To find the orthocenter I had to find the equation of the line containing the altitude of AC. X= 2 because it is a horizontal line. The line with the altitude of BC has a y value of -3. (2 − 5)/(4 − 5) The orthocenter of ∆ ABO is the same as point a (2,2). The orthocenter of ∆ ACO is point B (5,5) and the orthocenter of ∆ BCO is point c (2,2). What I found is that the orthocenter becomes the ve ...
Purchase document to see full attachment
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.
Studypool
4.7
Indeed
4.5
Sitejabber
4.4

Similar Documents

#14 5.03 questions Precalculus
...
Algebra Question
FACTOR BY GROUPING:2ay - 5xy + 2ab - 5xbThank you!!...
MCBS How Many Trees Should Be Planted per Acre in to Obtain Maximum Yield Questions
Pure Mathematics (FNDM PM2.1) – Spring - 20 – Supplementary (Assignment) –ALL – QP ` IN SEMESTER (INDIVIDUAL) AS...
Which of the following inequalities is shown in the graph, algebra homework help
Which of the following inequalities is shown in the graph below?...
Academy of Chinese Culture and Health Sciences Industrial Process Control Math Problems
Tutorial Questions 2: Industrial Process Control 1. Determine the system stability by root value using s-plan for followi...
Word problem - help!
Gina visited the aquarium with some of her cousins, aunts and uncles.  The group bought 20 admission tickets for $340...
Untitleddocument
9 is less than the product of M and N. “The product of M and N” is the same as “the sume of these two ( M and N ) th...
Math Problem Solution
Using quotient rule: logb x/y = logb x - logb y Using definition of common logarithm ba = x if and only if logb (x) =a...
Inverse Functions
1. If f(x) = 2x + 1 and g(x) = x2, what is f ○ g? What is g ○ f? 2. Consider f(x) = 2x + 3. Find the inverse of this f...