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Stoichiometry Lab

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User Generated
Subject
Chemistry
School
Milwaukee Area Technical College
Type
Homework
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Stoichiometry lab
Reaction of sodium carbonate with hydrochloric acid
(1) Balanced equation
1 Na
2
CO
3
(s) + 2 HCl(aq) 1 H
2
O(l) + 1 CO
2
(g) + 2 NaCl(aq)
(2) Data table
Mass empty crucible + lid = 33.076g
Mass crucible + lid + Na2CO3 = 33.651
Mass Na
2
CO
3
= 0.575g
Theoretical yield NaCl = 0.634g
Mass crucible + lid + NaCl = 33.653
Mass NaCl produced = 0.577g
% yield NaCl = 91.0%
(3) Calculations
Mass Na
2
CO
3
used


   
Theoretical yield NaCl












Mass NaCl produced
  
% yield






 
(4) Possible Error sources
a. Moisture in the sodium carbonate would lead to less sodium carbonate present, less
actual NaCl recovered and a lower % yield
b. Measuring of warm crucible + lid instead of cool crucible + lid will lead to lower mass
crucible + lid, higher mass sodium carbonate, higher theoretical yield and lower % yield
c. Spattering during the reaction or cooling will cause loss of NaCl, lower actual yield of
NaCl and lower % yield
d. Impurities of NaCl in the sodium carbonate are common. These will lead to lower actual
and lower % yield.

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Stoichiometry lab Reaction of sodium carbonate with hydrochloric acid (1) Balanced equation 1 Na2CO3(s) + 2 HCl(aq) → 1 H2O(l) + 1 CO2(g) + 2 NaCl(aq) (2) Data table Mass empty crucible + lid = 33.076g Mass crucible + lid + Na2CO3 = 33.651 Mass Na2CO3 = 0.575g Theoretical yield NaCl = 0.634g Mass crucible + lid + NaCl = 33.653 Mass NaCl produced = 0.577g % yield NaCl = 91.0% (3) Calculations Mass Na2CO3 used mass Na2 CO3 used = 33.651g − 33.076g = 0.575g Theoretical yield NaCl 0.575g Na2 CO3 1 mol Na2 CO3 2 mol NaCl 58.44g NaCl ∗ ∗ ∗ = 0.634g NaCl 1 106.0g Na2 CO3 1 mol N ...
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