Access over 20 million homework documents through the notebank

Get on-demand Q&A homework help from verified tutors

Read 1000s of rich book guides covering popular titles

.NET
Accounting
Algebra
Anatomy
App Development
Arithmetic
Art & Design
Biology
Botany
Business
Business Law
C Programming
Calculus
Chemistry
Communications
Computer Science
Ecology
Economics
Engineering
English
Environmental Science
Excel
Film
Genetics
Geography
Geology
Geometry
Graphs
Health & Medical
History
Html / CSS
Java
Javascript
jQuery / Prototype
Law
Linguistics
Linux
Management
Marketing
Mathematics
MathLab
Music
MySQL
Nursing
Nutrition
Philosophy
PHP
Physics
Pinterest
Political Science
Powerpoint
Probability
Programming
Psychology
Python
Science
Social Science
Software Development
Statistics
Swift
Trigonometry
Twitter
Website Design
Wordpress
Zoology

Accounting
Application Writing
Art & Design
Biology
Business
Chemistry
Communications
Computer Science
Economics
Engineering
English
Environmental Science
Film
French
Geography
Geology
Health & Medical
History
Law
Literature
Management
Marketing
Mathematics
Nursing
Philosophy
Physics
Poetry
Political Science
Powerpoint
Psychology
SAT
Science
Social Science
Spanish
Writing

homework answers & study documents

Showing Page:

1/1

a. There are 35 candies total, of which 6 are snickers. We want exactly 3 snickers from

the jar, so the probability is:

However, this expression only represents the probability that the first 3 are snickers

and the last is not. So, we just need to multiply this probability by 4 to get our final

answer:

b. Of the 35 candies, 26 are not cadburys. So, the probability that all 4 candies are not

cadburys is:

We don't need to take into account the order. So, the final answer is:

c. We will first find the probability that there are no butterfingers, then subtract that

probability from 1 to get the probability that there is at least one butterfinger. Since

22 of the 35 candies are not butterfingers, the probability that there are no

butterfingers is:

The probability that there are no butterfingers is thus . We subtract this quantity

from 1 to get the final answer: .

d. We will first find the probability that there are either exactly 3 or 4 hersheys, then

subtract that probability from 1 to find the probability that there are at most 2

hersheys. We know from part (a) that the probability that there are exactly 3

hersheys is . We can compute the probability that there are exactly 4 hersheys as

follows:

This evaluates to , and thus the probability there are either 3 or 4 hersheys is .

Subtracting this quantity from 1 gives the probability that there are at most 2

hersheys:

e. We already found the probability that there are no butterfingers in part (c). The

answer we found was

Sign up to view the full document!

a. There are 35 candies total, of which 6 are snickers. We want exactly 3 snickers fromthe jar, so the probability is:However, this expression only represents the probability that the first 3 are snickersand the last is not. So, we just need to multiply this probability by 4 to get our finalansw ...

Purchase document to see full attachment

Purchase document to see full attachment

Review

Review

Anonymous

I was on a very tight deadline but thanks to Studypool I was able to deliver my assignment on time.

Anonymous

I did not know how to approach this question, Studypool helped me a lot.

Anonymous

Very good notes! They were very useful as my study guides.

Studypool

4.7

Trustpilot

4.5

Sitejabber

4.4

Similar Documents

Mh Week1 Discussion

This is a process that I am involved daily. The activities that are involved in typing are; opening a word document and th...

Response 2

Amidst growing concern over the security of the organizations’ data, there is a need for the companies to make appropria...

Response Ssp

I agree with the author’s assertion that a system security plan allows organizations to evaluate their security needs, a...

Response 3

Red Clay Renovations has three locations. The system assessment carried out identified some deficiencies in the current sy...

Response 4

I concur with the author that a System Security Plan facilitates planning for secure, cost effective and sufficient IT req...

Ipv6.docx

One reason for IPv4 sub netting was the limited number of available IP addresses. As IPv4 is replaced with IPv6 describe t...

Studypool values your privacy. Only questions posted as Public are visible on our website.

Most Popular Study Documents

Copyright © 2020. Studypool, Inc.

Studypool is not sponsored or endorsed by any college or university.

Take 10 seconds to Sign up!

Get instant access to your document!

Access over 20 million homework documents through the notebank

Get on-demand Q&A homework help from verified tutors

Read 1000s of rich book guides covering popular titles

Login

or
Sign Up

Become A Tutor

OR

Sign up with:

Honor Code

By signing up, I agree to follow Stuydpool’s Honor Code

Our Partner Countries

These are the countries currently available for verification, with more to come!

United States

Canada

Mexico

Europe(Continental)

South Africa

China

Israel

Japan

South Korea

Australia

New Zealand

Argentina

Brazil

Chile