Chemistry Questions 1. In the unbalanced reaction, Cr + HNO3 -----> Cr(NO3)3 + N2O3+ H2O, 9.050 grams of Cr(NO3)3 was formed. How many N2O3 molecules were formed and how many grams of HNO3 were reacted? 𝐵𝑎𝑙𝑎𝑛𝑐𝑒𝑑 𝑟𝑒𝑎𝑐𝑡𝑖𝑜𝑛: 4 𝐶𝑟 + 18 𝐻𝑁𝑂3 → 4 𝐶𝑟(𝑁𝑂3)3 + 3 𝑁2𝑂3 + 9 𝐻2𝑂 𝑁2𝑂3: 1 𝑚𝑜𝑙𝑒 3 𝑚𝑜𝑙𝑒 𝑁2𝑂3 6.022 𝑥 10!" 𝑚𝑜𝑙𝑒𝑐𝑢𝑙𝑒𝑠 9.050 𝑔 𝐶𝑟(𝑁𝑂3)3 𝑥 𝑥 𝑥 = 1.717 𝑥 10!" 𝑚𝑜𝑙𝑒𝑐𝑢𝑙𝑒𝑠 238 𝑔 4 𝑚𝑜𝑙𝑒 𝐶𝑟(𝑁𝑂3)3 1 𝑚𝑜𝑙𝑒 𝐻𝑁𝑂3: 1 𝑚𝑜𝑙𝑒 18 𝑚𝑜𝑙𝑒𝑠 𝐻𝑁𝑂3 63𝑔 9.050 𝑔 𝐶𝑟(𝑁𝑂3)3 𝑥 𝑥 𝑥 = 10.8 𝑔𝑟𝑎𝑚𝑠 𝐻𝑁𝑂3 238 𝑔 4 𝑚𝑜𝑙𝑒𝑠 𝐶𝑟(𝑁𝑂3)3 1 𝑚𝑜𝑙𝑒 𝐻𝑁𝑂3 2. By now, you all know that silver iodide is very insoluble in water. Chemists know that by adding a very slight excess of silver nitrate to an iodide containing solution it is possible effectively to remove all the iodide ion from the sample. First, write a balanced net ionic equation for this reaction. ...
Purchase document to see full attachment