# B095 Module 05 Written Equations Exercises

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B095 Module 05 Written Assignment
Instructions: All problems are worth 5 points. Make sure you are showing all steps and explaining
yourself in detail in the boxes below the problems for full points. Try using the equation editor to show
your work. If needed, you may write your steps out by hand and upload a scanned version of the
homework.
1. Provide the codeword given in the Module 05 Part 1 Live Lecture.
2. Provide the codeword given in the Module 05 Part 2 Live Lecture.
3. Solve the following system of equations using elimination.
   
  
On my block and the 100
ALMOST DONE
Solve and show all work here. You must check your solution at the end!
    2x 2y = -7
X 2y = - 4 2x 2(0.5) = -7
X 2y = - 4 * 2 2x + 1 = -7
X * 2= 2x -1 -1
-2y *2= -4y 0 -8
-4 * 2= -8 2x/2 = -8/2
2x-2y=-7 x = -4
2x-4y=-8 Solution is (-4, 0.5)
0-2y=-1
-2y/-2 =--1/-2
Y = 0.5

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4. Solve the following system of equations using substitution.
  
  
Solve and show all work here. You must check your solution at the end!

  
 
6y + 27 + y = 2
6y + y= 7y
7y + 27 = 2
-27 -27
7y = -25
7y/7 = -25/7
Y = -3.57
X = -2y + 9
X = -2 (-3.57) +9
X = 7.14 + 9
X = 16.14
Solution is (16.14, -3.57)

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B095 Module 05 Written Assignment Instructions: All problems are worth 5 points. Make sure you are showing all steps and explaining yourself in detail in the boxes below the problems for full points. Try using the equation editor to show your work. If needed, you may write your steps out by hand and upload a scanned version of the homework. 1. Provide the codeword given in the Module 05 – Part 1 Live Lecture. On my block and the 100 2. Provide the codeword given in the Module 05 – Part 2 Live Lecture. ALMOST DONE ☺ 3. Solve the following system of equations using elimination. 2𝑥 − 2𝑦 = −7 𝑥 − 2𝑦 = −4 Check your answer by plugging it back into BOTH equations. Solve and show all work here. You must check your solution at the end! 2𝑥 − 2𝑦 = −7 2x – 2y = -7 X – 2y = - 4 2x – 2(0.5) = -7 X – 2y = - 4 * 2 2x + 1 = -7 X * 2= 2x -2y *2= -4y -4 * 2= -8 2x-2y=-7 2x-4y=-8 0-2y=-1 -2y/-2 =--1/-2 Y = 0.5 -1 0 -1 -8 2x/2 = -8/2 x = -4 Solution is (-4, 0.5) 4. Solve the following system of equations using substitution. 3𝑥 + 𝑦 = 2 𝑥 = −2𝑦 + 9 Check your answer by plugging it back into BOTH equations. Solve and show all work he ...
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