Access over 20 million homework & study documents

Ex1

Content type
User Generated
Subject
Statistics
School
Cuyahoga Community College
Type
Homework
Rating
Showing Page:
1/3
GC1055 SR 8-9
20201017204245ex1 ` Date Last Saved 2020-10-14 @ 02:25
Date Last Saved 2020-10-14 @ 02:25
Chapter
Modified
page
Section in Textbook
8
Ex. 8-9
8.9 Using the Sampling Distribution of the Sample Mean
and the Central Limit Theorem
In the law firm Tybo and Associates, there are six partners. Listed next is the number of cases
each partner actually tried I court last month.
Partner
Number of Cases
Ruud
3
Wu
6
Sass
3
Flores
3
Wilhelms
0
Schueller
1
a. How many different samples of size 2 are possible? Show the details of your
calculations indetai. Hint: Use the Combination Equation [Eq. 5-10]
С(6,2)=6!/(2!(6-2)!)=6!/(2!*4!)=(6*5)/(2*1)=15
b. List all possible samples of size 2, and compute the mean number of cases in each
sample.
(Ruud, Wu), (Ruud, Sass), (Ruud, Flores), (Ruud, Wilhelms), (Ruud, Schueller), (Wu, Sass),
(Wu, Flores), (Wu, Wilhelms), (Wu, Schueller), (Sass, Flores), (Sass, Wilhelms), (Sass,
Schueller), (Flores, Wilhelms), (Flores, Schueller), (Wilhelms, Schueller).
The corresponding means, in this order, are:
1).(3+6)/2=4.5
2). (3+3)/2=3
3). (3+3)/2=3
4). (3+0)/2=1.5
5). (3+1)/2=2
6). (6+3)/2=4.5
7). (6+3)/2=4.5
8). (6+0)/2=3
9). (6+1)/2=3.5
10). (3+3)/2=3
11). (3+0)/2=1.5
12). (3+1)/2=2
13). (3+0)/2=1.5
14). (3+1)/2=2
15). (0+1)/2=0.5

Sign up to view the full document!

lock_open Sign Up
Showing Page:
2/3
GC1055 SR 8-9
20201017204245ex1 ` Date Last Saved 2020-10-14 @ 02:25
Date Last Saved 2020-10-14 @ 02:25
c. Compare the mean of the distribution of sample means to the population mean.
Population mean:
(3+6+3+3+0+1)/6=2.67
Mean of sample means:
(4.5+3+3+1.5+2+4.5+4.5+3+3.5+3+1.5+2+1.5+2+0.5)/15=2.67
(4.5+3+3+1.5+2+4.5+4.5+3+3.5+3+1.5+2+1.5+2+0.5)/15=2.67
The population mean is equal to the mean of sample means.
d. On charts similar to Chart 8-2 on page 258 in the textbook, taking into
consideration the Central Limit Theorem, discuss the difference in the dispersion in the
population with that of the sample means.
The dispersion of a sample mean is equal to the population dispersion, divided by the
square root of the sample size. Thus, the larger the sample size, the smaller the
population dispersion.
For example, if mu=5, and SD=3, the population distribution will look approximately like
this. About 95% of values will lie within 2 Sds of the mean, between -1 and 11.

Sign up to view the full document!

lock_open Sign Up
Showing Page:
3/3

Sign up to view the full document!

lock_open Sign Up
Unformatted Attachment Preview
GC1055 – SR 8-9 Chapter Modified 8 Ex. 8-9 page Section in Textbook 8.9 Using the Sampling Distribution of the Sample Mean and the Central Limit Theorem In the law firm Tybo and Associates, there are six partners. Listed next is the number of cases each partner actually tried I court last month. Partner Ruud Wu Sass Flores Wilhelms Schueller Number of Cases 3 6 3 3 0 1 a. How many different samples of size 2 are possible? Show the details of your calculations indetai. Hint: Use the Combination Equation [Eq. 5-10] С(6,2)=6!/(2!(6-2)!)=6!/(2!*4!)=(6*5)/(2*1)=15 b. List all possible samples of size 2, and compute the mean number of cases in each sample. (Ruud, Wu), (Ruud, Sass), (Ruud, Flores), (Ruud, Wilhelms), (Ruud, Schueller), (Wu, Sass), (Wu, Flores), (Wu, Wilhelms), (Wu, Schueller), (Sass, Flores), (Sass, Wilhelms), (Sass, Schueller), (Flores, Wilhelms), (Flores, Schueller ...
Purchase document to see full attachment
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Anonymous
I was struggling with this subject, and this helped me a ton!

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4