Access over 20 million homework & study documents

Thermodynamic Questions Solved

Content type
User Generated
Subject
Engineering
School
Delaware State University
Type
Homework
Rating
Showing Page:
1/4
Q1.
To solve this problem, first we have to determine the fluid state of aggregation, which can be done
with the calculation of the approximated value of the vapor saturation pressure using the shortcut
vapor pressure equation since P > 2 bar:


 
 
,






Thus,








Since P = 0.8 MPa <

, the octane is vapor. Therefore, we can use the virial equation method
for the calculation of the fugacity coefficient of a gas as long as the restriction conditions are
satisfied. These conditions are subject to:
  
, which for this case equals:
  


Since 0.8273 < 1.0197, the condition is met, and the calculation of the fugacity coefficient is very
straightforward with the following equations:



 

  

  

Plugging into numbers:











Sign up to view the full document!

lock_open Sign Up
Showing Page:
2/4
  

 



And:







Which makes sense since the pressure is not so high. The value of the fugacity is then:


 MPa

Sign up to view the full document!

lock_open Sign Up
Showing Page:
3/4

Sign up to view the full document!

lock_open Sign Up
End of Preview - Want to read all 4 pages?
Access Now
Unformatted Attachment Preview
Q1. To solve this problem, first we have to determine the fluid state of aggregation, which can be done with the calculation of the approximated value of the vapor saturation pressure using the shortcut vapor pressure equation since P > 2 bar: 7 1 log 𝑃𝑟𝑠𝑎𝑡 ≈ (𝜔 + 1) (1 − ) 3 𝑇𝑟 𝑇 𝑃 𝑇𝑟 = 𝑇 , 𝑃𝑟 = 𝑃 𝐶 𝐶 𝑇𝑟 = 580 = 1.0197 568.8 𝑃𝑟 = 0.8 = 0.3218 2.486 Thus, 𝑃 𝑠𝑎𝑡 ≅ 𝑃𝐶 ∙ 10 7(1+0.396) 1 (1− ) 3 1.0197 = 2.486(1.1148) = 2.7714 Since P = 0.8 MPa < 𝑃 𝑠𝑎𝑡 , the octane is vapor. Therefore, we can use the virial equation method for the calculation of the fugacity coefficient of a gas as long as the restriction conditions are satisfied. These conditions are subject to: 𝑇𝑟 > 0.686 + 0.439𝑃𝑟 , which for this case equals: 0.686 + 0.439(0.3218) = 0.8273 Since 0.8273 < 1.0197, the condition is met, and the calculation of the fugacity coefficient is very straightforward with the following equations: ln 𝜑 = 𝐵𝑃 𝑅𝑇 𝐵 = (𝐵0 + 𝜔𝐵1 )𝑅𝑇𝐶 /𝑃𝐶 𝐵0 = 0.083 − 0.422/𝑇𝑟 1.6 𝐵1 = 0.139 − 0.172/𝑇𝑟 4.2 Plugging into numbe ...
Purchase document to see full attachment
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Anonymous
I was having a hard time with this subject, and this was a great help.

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4