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3) Given: [HNO₂2] = 0.0516 M pH = 2.34 HNO₂ (aq) + H₂0 (1) = H₂O + (aq) + NO₂ (aq) HNO2 = 0.0516 H30+ = x NO₂ [H₂O*] 10-2-34 Km. [H₂O* ][ NO₂ (HNO₂) Ka' (0-0046 )(00046) (0-0470) Ka' 4-5 -101 HNO₂ = 0.0516-0.0046 = 0.0470 M H30+ = 0.0046M NO ₂ = 0·0046 M •0-0046 M X ...
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