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Civil engineering hydrualic design dam crest level

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CE311-ASSIGNMENT 3 COMPUTATION OF DAM CREST LEVEL JAYASUNDARA H.P.M.A.P E/15/155 SEMESTER 06 1 Location Of Dam Axis N = Remainder (Reg no/3) = Remainder (155/3) =1 Therefore, Dam axis 2 =2 Type Of Dam N = Remainder (Reg no/2) = Remainder (155/2) =1 Therefore, Type of damp = Embankment dam 3 Volume Behind Dam Axis Table 3.1 Elevation above MSL (m) Surface area (m2) volume Between two adjacent contour surface Cumulative Volume (MCM) 735 740 745 750 755 760 765 770 775 4,250 20,250 61,750 124,750 222,250 339,250 482,750 630,250 842,500 61250 205000 466250 867500 1403750 2055000 2782500 3681875 0.06125 0.26625 0.67125 1.33375 2.27125 3.45875 4.8375 6.464375 780 785 790 795 800 805 1,044,500 1,251,000 1,512,250 1,823,000 2,182,000 2,608,000 4717500 5738750 6908125 8338125 10012500 11975000 Required capacity of reservoir = 10.8MCM Assuming volume varies linearly between two contours, 10.8 − 10.45625 12.646878 − 10.45625 = 𝑋 − 785 790 − 785 X = 785.785m Fully supply level of reservoir = 785.785m Maximum afflux = 2.19m High flood level (HFL) = 785.785+2.19 = 787.975m 4 Wind Speed N = Remainder (Reg no/4) = Remainder (355/4) =3 Therefore, Wind speed = 90km/h = 25m/s 5 Wind Set-up And Nominal Freeboard N = Remainder (Reg no/4) = Remainder (355/4) =3 8.399375 10.45625 12.646875 15.24625 18.350625 21.9875 Therefore, Nominal freeboard = 2m Wind set-up = 0.1m Figure 5.1: Inundation area at HFL of reservoir From figure 5.1, F = ...
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