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Che calculations 2 solid fuel reviewer

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CHE CALCULATIONS 2 REVIEWER SOLID FUELS (TYPE I) 1. A sample of lignite was found to contain 34.55% moisture, 22.91% FC, 7.2% Ash, 1.1% Sulfur, and 0.57% Nitrogen with a calorific value of 16.45 MJ/kg. Calculate: a. Proximate Analysis b. Modified Analysis c. Ultimate Analysis d. Analysis of VCM e. Calorific Value of VCM Given: 34.55% Moisture 22.91% Fixed Carbon 7.2% Ash 1.1% Sulfur 0.57% Nitrogen Lignite CV = 16.45 MJ/kg Required: a. Proximate Analysis b. Modified Analysis c. Ultimate Analysis d. Analysis of VCM e. Calorific Value of VCM Solution: %VCM = 100 – Moisture – Fixed Carbon – Ash %VCM = 100 – 34.55 – 22.91 – 7.2 %VCM = 35.34% Proximate Analysis: FC VCM Ash Moisture Total 22.91% 35.34% 7.2% 34.55% 100.00% %C = 5.88 + 2.206(CV – 0.094S) + 0.0053[80 – 100 (VCM/FC)]1.55 35.34 1.55 %C=5.88+2.206[16.45-0.094(1.1)]+0.0053 |80-100∙ | 22.91 %C = 46.15% CV=0.338 ∙C+1.44 (H(H- O ) +0.094 ∙S 8 O ) = Net Hydrogen (NH) 8 therefore, CV=0.338 ∙C+1.44 ∙NH+0.094 ∙S NH= CV-0.338 ∙C-0.094 ∙S 1.44 NH= 16.45-0.338(46.15)-0.094(1.1) 1.44 NH = 0.52% Combined Water (CW) = 100 – NH – C – Moisture – N – S – Ash CW = 100 – 0.52 – 46.15 – 34.55 – 0.57 – 1.1 – 7.2 CW = 9.91% Modified Analysis: C N S Ash Moisture Net Hydrogen Combined Water Total 100% 46.15% 0.57% 1.1% 7.2% 34.55% 0.52% 9.91% Hydrogen in CW & M = (9.91 + 34.55)(2/18) Hydrogen in CW & M = 4.94 Total Hydrogen = Hydrogen in CW & M + Net Hydrogen Total Hydrog ...
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