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# Monthto Numeric Variables and Create of A New Variable Code Notes

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Homework 2 - dplyr
Due 10/27 by Midnight
library(dplyr)
library(tidyr)
library(ggplot2)
Part 1 - Cleaning without dplyr
Instructions:
Without using dplyr
Each of the above should be one line of code.
zillow <-
stringsAsFactors=F)
1. Remove the RegionID and SizeRank columns
zillow2 = zillow[ , -c(1, 3)]
2. Reshape the data appropriately using the gather() function
zillow2 = gather(zillow2, 'Date', 'Sales', -RegionName)
3. Remove the X from the variable containing the date information
zillow2\$Date = gsub('X', '', zillow2\$Date)
4. Using the separate() function, split the column containing the date information into
Year and Month columns
zillow2 = separate(zillow2, Date, c('Year', 'Month'), sep = '\\.')
5. Convert Year to a numeric variable
zillow2\$Year = as.numeric(zillow2\$Year)
6. Convert Month to a numeric variable
zillow2\$Month = as.numeric(zillow2\$Month)
7. Create a new variable, Date, defined as Year+Month/12 (I want this variable for easy
plotting)
zillow2\$Date = zillow2\$Year + (zillow2\$Month / 12)
8. Remove any rows where the median sale price is missing (hint: you can use is.na(x)
to identify missing values, or !is.na(x) to identify non-missing value, where x is the
column you are interested in, both will return a TRUE/FALSE vector)

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zillow2 = zillow2[!is.na(zillow2\$Sales), ]
9. Order the data by state and date (hint: data = data[order(variable1, variable2),
])
zillow2 = zillow2[order(zillow2\$RegionName, zillow2\$Date), ]
10. Print out the data structure using the str() function
str(zillow2)
'data.frame': 3994 obs. of 5 variables:
\$ RegionName: chr "Alabama" "Alabama" "Alabama" "Alabama" ...
\$ Year : num 2012 2012 2012 2012 2012 ...
\$ Month : num 6 7 8 9 10 11 12 1 2 3 ...
\$ Sales : num 108800 111500 112200 115400 115000 ...
\$ Date : num 2012 2013 2013 2013 2013 ...
Part 2 - Cleaning with dplyr
Instructions:
1. select - Remove the RegionID and SizeRank columns
2. Reshape the data appropriately using the gather() function
3. mutate - Remove the X from the variable containing the date information
4. Using the separate() function, split the column containing the date information into
Year and Month columns
5. mutate - Convert Year and Monthto numeric variables, and create a new variable, Date,
defined as Year+(Month/12)
6. filter - Remove any rows where the median sale price is missing
7. arrange - Order the data by state and date
When finished, connect your dplyr chain to the original read.csv() statement, so your
select() %>%
mutate()...
zillow <-
stringsAsFactors=F)
zillow2 = zillow %>%
select(-RegionID, -SizeRank) %>%
gather('Date', 'Price', -RegionName) %>%
mutate(Date = gsub('X', '', Date)) %>%
separate(Date, c('Year', 'Month'), sep = '\\.') %>%
mutate(
Year = as.numeric(Year),
Month = as.numeric(Month),

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Homework 2 - dplyr Due 10/27 by Midnight First, load the packages needed. library(dplyr) library(tidyr) library(ggplot2) Part 1 - Cleaning without dplyr Instructions: Without using dplyr… Each of the above should be one line of code. zillow Purchase document to see full attachment
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